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Question : 3
Total: 7
Consider the carbon compounds having following molecular formula:(i) C 2 H 2 (ii) C 2 H 6 (iii) C 3 H 7 OH
(iv)C 2 H 5 COOH (v) CH 3 CHO
(a) Identify which one of the above compounds, is a member of aldehyde series.
(b) Write the general formula of the series to which compoundC 2 H 2 belongs.
(c) Which one of the above compounds has triple bonds between carbon - carbon atoms?
(d) Write the molecular formula of the first member of the homologous series to which the compoundC 3 H 7 OH belongs.
(iv)
(a) Identify which one of the above compounds, is a member of aldehyde series.
(b) Write the general formula of the series to which compound
(c) Which one of the above compounds has triple bonds between carbon - carbon atoms?
(d) Write the molecular formula of the first member of the homologous series to which the compound
Solution:
(a) Acetaldehyde ( CH 3 CHO ) is a member of aldehyde series.
(b) Ethyne( C 2 H 2 ) is the first member of the alkyne family, with two carbon atoms connected by a triple bond. Alkynes comprise a series of carbon and hydrogenbased compounds that contain at least one triple bond. This group of compounds is a homologous series with the general molecular formula of C n H 2 n − 2 ′ , where n equals to any integer greater than one.
(c) Ethyne( C 2 H 2 ) have two carbon atoms connected by a triple bond.
(d)C 3 H 7 OH belongs to the homologous series with general formula of
C n H ( 2 n + 1 ) OH
The first member of this series is
C 1 H ( 2 ( 1 ) + 1 ) OH = CH 3 OH methanol.
(b) Ethyne
(c) Ethyne
(d)
The first member of this series is
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