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CBSE Class 12 Chemistry 2014 Outside Delhi Set 1 Solved Paper

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Question : 23 of 30
Marks: +1, -0
(i) Write the IUPAC name of the complex [Cr(NH3)4Cl2]Cl[\mathrm{Cr}(\mathrm{NH}_3)_4\mathrm{Cl}_2]\mathrm{Cl}.
(ii) What type of isomerism is exhibited by the complex [Co(en)3]3+[\mathrm{Co}(\mathrm{en})_3]^{3+} ?
(en = ethane-1, 2-diamine)
(iii) Why is [NiCl4]2[\mathrm{NiCl}_4]^{2-} paramgnetic but [Ni(CO)4][\mathrm{Ni}(\mathrm{CO})_4] is diamagnetic
(At. nos.: Cr=24, Co=27, Ni=28\mathrm{Cr}=24,\ \mathrm{Co}=27,\ \mathrm{Ni}=28 )
Solution:  
(i) The IUPAC name of [Cr(NH3)4Cl2]Cl[\mathrm{Cr}(\mathrm{NH}_3)_4\mathrm{Cl}_2]\mathrm{Cl} is Tetraam minedichlorochromium(III) chloride.
(ii) The isomerism exhibited by this complex is the optical isomerism.
(iii) The oxidation state of Ni\mathrm{Ni} in [NiCl4]2[\mathrm{NiCl}_4]^{2-} is +2 . Since chloride is a weak field ligand, it does not cause electron pairing up in opposition to Hund's maximum multiplicity rule. As a result, Ni's valence dd-orbitals contain two unpaired electrons, giving the complex its paramagnetic properties. On the other hand, carbonyl is a strong field ligand and causes electron partnering up in opposition to Hund's maximisation rule. As a result, there are no unpaired electrons and the complex is hence diamagnetic.
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