CBSE Class 12 Chemistry 2020 Delhi Set 1 Solved Paper

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Question : 35
Total: 37
SECTION -D

(a) Give reasons:
(i) Transition metals and their compounds show catalytic activities.
(ii) Separation of a mixture of Lanthanoid elements is difficult.
(iii) Zn,Cd and Hg are soft and have low melting point.
(b) Write the preparation of the following :
(i) Na2Cr2O7 from Na2CrO4
(ii) K2MnO4 from MnO2
OR
(a) Account for the following:
(i) Ti3+ is coloured whereas Sc3+ is colourless in aqueous solution.
(ii) Cr2+ is a strong reducing agent.
(b) Write two similarities between chemistry of lanthanoids and actinoids.
(c) Complete the following ionic equation:
3MnO42+4H+
Solution:  
(a) (i) The catalytic activities of transition metals and their compounds is due to the ability of adopt variable oxidation states and to form complexes. It can also provide a large surface area for the reactants to be adsorbed. (Any one)
(ii) Separation of lanthanoid elements is difficult because all lanthanoid elements have almost similar physical as well as chemical properties. Due to the lanthanoid contraction the change in the atomic or ionic radii is very small.
(iii) Zn,Cd and Mg are soft and have low melting point because no d-orbitals are available for metallic bond formation and bonds formed are very weak.
(b) (i) 2Na2CrO4+H2SO4 Na2Cr2O7+Na2SO4+H2O
(ii) 2MnO2+4KOH+O22K2MnO4 +2H2O
OR
(a) (i) Ti3+ has incomplete d(3d1) orbital whereas Sc3+ has empty (3d)d-orbital.
(ii) Cr2+ ion can lose electron to form Cr3+, so acts as a strong reducing agent.
(b) Similarities between chemistry of lanthanoids and actinoids:
(i) Both show +3 oxidation state.
(ii) Both are strong reducing agents.
(c) 3MnO42+4H+2MnO4 +MnO2+2H2O
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