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Question : 32
Total: 35
Rahul set-up an experiment to find resistance of aqueous K C l solution for different concentrations at 298 K using a conductivity cell connected to a Wheatstone bridge. He fed the Wheatstone bridge with a.c. power in the audio frequency range 550 to 5000 cycles per second. Once the resistance was calculated from null point he also calculated the conductivity K and molar conductivity ∧ m and recorded his readings in tabular form.
Answer the following questions:
(a) Why does conductivity decrease with dilution?
(b) If∧ ° m of K C l is 150.0 S cm mol − 1 , calculate the degree of dissociation of 0.01 M KCl .
(c) If Rahul had usedH C l instead to K C l then would you except the ∧ m values to be more or less than those per K C l for a given concentration. Justify.
OR
(c) Amit, a classmate of Rahul repeated the same experiment withC H 3 C O O H solutioninsteadof K C l solution. Give one point that would be similar and one that would be different in his observations as compared to Rahul.
S.No. | Conc.(M) | k S cm | |
---|---|---|---|
1. | 1.00 | | 111.3 |
2. | 0.10 | | 129.0 |
3. | 0.01 | | 141.0 |
(a) Why does conductivity decrease with dilution?
(b) If
(c) If Rahul had used
OR
(c) Amit, a classmate of Rahul repeated the same experiment with
Solution: 👈: Video Solution
(a) Conductivity decreases with dilution because it depends upon the number of ions present in the solution. When dilution increases number of available ions decreases. Hence, conductivity decreases.
(b)∝ =
i m = 150.0 S cm 2 mol − 1
i ° m = 141.0 S cm 2 mol − 1
∝ =
= 0.94
(c) Molar conductivity ofH C l will be high because when it break down into ions, it produce
H C l → H + + C l −
ItsH + (cation) size is smallerthen K + ion. So for same concentration of H C l and K C l , H C l shows high molar conductivity.
[OR]
(c) (i)K C l is strong electrolyte and completely dissociate into their respective ion while C H 3 − C O O H is weak electrolyteand do not completely dissociate.
(ii) Number of ions produced after dissociation are equal
K C l → K + + C l −
C H 3 − C O O H → C H 3 − C O O − + H +
(b)
(c) Molar conductivity of
Its
[OR]
(c) (i)
(ii) Number of ions produced after dissociation are equal
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