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CBSE Class 12 Math 2019 Delhi Set 3 Solved Paper

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Question : 6 of 10
Marks: +1, -0
Using properties of determinants, prove the following :
∣abca−bb−cc−ab+cc+aa+b∣=a3+b3+c3−3abc\begin{vmatrix} a & b & c \\ a-b & b-c & c-a \\ b+c & c+a & a+b \end{vmatrix} = a^3 + b^3 + c^3 - 3abc
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