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CBSE Class 12 Math 2020 Outside Delhi Set 1 Solved Paper

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Question : 22 of 36
Marks: +1, -0
Find the value of dydx\frac{dy}{dx} at θ=π3\theta = \frac{\pi}{3}, if x=cosθcos2θ,y=sinθsin2θx = \cos \theta - \cos 2\theta, y = \sin \theta - \sin 2\theta.
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