Given,
A={1,2,3,4,5,6}
R={(x,y):y‌ is divisible by ‌x}
(i) (2,4)∈R    {∵4 is divisible by 2 }
But (4,2)∉ R {∵2 is not divisible by 4}
∴‌‌R is not symmetric.
 

(ii) Let (a,b)∈R&(b,c)∈R
⇒‌‌b=λa and c=µb
Now, c=µb=µ(λa)⇒(a,c)∈R
⇒‌‌c is divisible by a
∴‌‌R is transitive.
 
OR
‌ L.H.S. ‌=‌

9π

8

−‌

9

4

sin‌−1‌

1

3

=‌

9

4

(‌

π

2

−sin‌−1‌

1

3

)
=‌

9

4

(cos−1‌

1

3

).....(1)
Now, let cos−1‌

1

3

=x .
Then, cos‌x=‌

1

3

⇒sin‌x=√1−(‌

1

3

)2=‌

2√2

3

∴x=sin‌−1‌

2√2

3

⇒cos−1‌

1

3

=sin‌−1‌

2√2

3

∴‌ L.H.S. ‌=‌

9

4

sin‌−1‌

2√2

3

=‌ R.H.S. ‌