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CBSE Class 12 Math 2023 All Sets Solved Paper

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Question : 7 of 20
Marks: +1, -0
Equation of line passing through origin and making 30,6030^{\circ} , 60^{\circ} and 9090^{\circ} with x, y, z axes respectively is:
Solution:  
Direction cosines is given by (cosα,cosβ,cosγ)(cos30,cos60,cos90)(  32,  12,0)(\cos \alpha, \cos \beta, \cos \gamma) \equiv (\cos 30^{\circ}, \cos 60^{\circ}, \cos 90^{\circ}) \equiv \left(\;\frac{\sqrt{3}}{2}, \;\frac{1}{2}, 0\right)
Equation of the line is:
  x032=  y012=  z00\;\frac{x-0}{\frac{\sqrt{3}}{2}} = \;\frac{y-0}{\frac{1}{2}} = \;\frac{z-0}{0}
  2x3=  2y1=  z0\Rightarrow \;\frac{2x}{\sqrt{3}} = \;\frac{2y}{1} = \;\frac{z}{0}
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