If A=\left[\begin{array}{cc}1 & 0 \ 2 & 1]\end{array}, ...

CBSE Class 12 Math 2023 Delhi Set 1 Solved Paper

© examsnet.com

Question : 4 of 38

Marks: +1, -0

If

A={[\table 1 , 0 ; 2 , 1]}, B={[\table x , 0 ; 1 , 1]}

and

A=B^2

, then

x

equals:

± 1
-1
1
2

Solution: 👈: Video Solution

A\;=B^2

\;{{[\table 1 , 0 ; 2 , 1 ]}}\;={[\table x , 0 ; 1 , 1 ]}{[\table x , 0 ; 1 , 1 ]}

∴ \; \;\; {[\table 1 , 0 ; 2 , 1 ]}\;={[\table x^2 , 0 ; x+1 , 1 ]}

∴ \;x^2\;=1 \;\text " and "\; x+1=2

∴ \; \;\; x\;= ± 1

\;x\;=1

Hence

x=1

© examsnet.com

Go to Question:

Prev Question

Next Question