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CBSE Class 12 Math 2023 Delhi Set 1 Solved Paper

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Question : 5 of 38
Marks: +1, -0
If ∣α34121141∣=0\begin{vmatrix} \alpha & 3 & 4 \\ 1 & 2 & 1 \\ 1 & 4 & 1 \end{vmatrix}=0, then the value of α\alpha is:
Solution:     👈: Video Solution
Explanation:
[α34121141]=0\begin{bmatrix} \alpha & 3 & 4 \\ 1 & 2 & 1 \\ 1 & 4 & 1 \end{bmatrix}=0
⇒α(2−4)−3(1−1)+4(4−2)=0\Rightarrow \alpha(2-4)-3(1-1)+4(4-2)=0
−2α+8=0-2\alpha+8=0
α=4\alpha=4
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