Test Index

CBSE Class 12 Math 2025 All Sets Solved Paper

© examsnet.com
Question : 12 of 20
Marks: +1, -0
The absolute maximum value of function f(x)=x3−3x+2 in [0, 2] is
Solution:  
f(x)=x3−3x+2,x∈[0,2]
To check extremum, differentiate,
f′(x)=3x2−3
⇒f′(x)=0⇒3(x2−1)=x=±1
⇒ Critical points are -1, 1 and end points 0, 2
⇒f(0)=2
f(1) = 0
f(2)=23−3(2)+2=8−6+2=4
absolute maximum value is 4
© examsnet.com
Go to Question:
Prev Question
Next Question