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CBSE Class 12 Math 2025 All Sets Solved Paper

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Question : 13 of 20
Marks: +1, -0
The order and degree of differential function [1+(  dydx)2]5=d2ydx2\left[ 1+ \left( \; \frac{d y}{d x} \right)^{2} \right]^{5} = \frac{d^{2}}{y} d x^{2} are
Solution:  
The equation is
[1+(  dydx)2]5=(d2ydx2)1\left[ 1+ \left( \; \frac{d y}{d x} \right)^{2} \right]^{5} = \left( \frac{d^{2}}{y} d x^{2} \right)^{1}
The highest derivative is (  d2ydx2)1\left( \; \frac{d^{2}}{y} d x^{2} \right)^{1}
⇒\Rightarrow Order of differential equation is 2
⇒\Rightarrow The exponent of highest derivative is 1
Therefore, degree of differential equation is 1
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