CBSE Class 12 Physics 2014 Delhi Set 1 Paper

Question : 16

Total: 30

An electric dipole of length 4‌cm, when placed with its axis making an angle of 60∘ with a uniform electric field, experiences a torque of 4√3‌Nm. Calculate the potential energy of the dipole, if its has charge ±8‌nC.

Solution:

τ‌=pEsin‌θ
4√3‌=pEsin‌θ
pE‌

√3

‌=4√3
So, ‌‌pE=8
Potential energy of the dipole =−pE‌cos‌θ
‌U=−pE‌cos‌60
‌U=−8×0.5
‌U=−4J

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