CBSE Class 12 Physics 2014 Delhi Set 1 Paper

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Question : 18
Total: 30
(i) Monochromatic light of frequency 6.0×1014Hz is produced by a laser. The power emitted is 2.0× 103W. Estimate the number of photons emitted per second on an average by the source.
(ii) Draw a plot showing the variation of photoelectric current versus the intensity of incident radiation on a given photosensitive surface.
Solution:  
(i) An energy,
E=hv
=6.63×1034×6.05×1014
=3.98×1019J
Now,number of photons emitted per second
n=
p
E
=2.0×
103
3.98
×1019J

=5×1015 photons per second
(ii)
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