CBSE Class 12 Physics 2014 Delhi Set 3 Paper

Question : 4

Total: 8

An electric dipole of length 2‌cm , when placed with its axis making an angle of 60∘ with a uniform electric field, experiences torque of 6√3‌Nm . Calculate the potential energy of the dipole, if it has a charge of ±2nC .

Solution:

τ‌=pEsin‌θ
6√3‌=pEsin‌θ
pE‌

√3

‌=6√3
So, pE=12
Potential energy of the dipole =−pE‌cos‌θ
‌U=−pE‌cos‌60∘
‌U=−12×0.5
‌U=−6J

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