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CBSE Class 12 Physics 2018 Delhi Set 1 Paper

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Question : 10 of 26
Marks: +1, -0
A carrier wave of peak voltage 15 V15\,\mathrm{V} is used to transmit a message signal. Find the peak voltage of the modulating signal in order to have a modulation index of 60%60\%.
Solution:  
Formula for modulation index
Finding the peak value of the modulating signal
We have, μ=AmAc\mu = \frac{A_m}{A_c}
Here, μ=60%=35\mu = 60\% = \frac{3}{5}
∴Am=μAc=35×15 V=9 V\therefore A_m = \mu A_c = \frac{3}{5} \times 15\,\mathrm{V} = 9\,\mathrm{V}
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