© examsnet.com
Question : 12
Total: 26
(a) Define the term 'conductivity' of a metallic wire. Write its SI unit.
(b) Using the concept of free electrons in a conductor, derive the expression for the conductivity of a wire in terms of number density and relaxation time. Hence obtain the relation between current density and the applied electric fieldE .
(b) Using the concept of free electrons in a conductor, derive the expression for the conductivity of a wire in terms of number density and relaxation time. Hence obtain the relation between current density and the applied electric field
Solution:
(a) Definition and SI unit of conductivity
(b) Derivation of the expression for conductivity
Relation between current density and electric field
(a) The conductivity of a material equals to the reciprocal of the resistance of its wire of unit length and unit area of cross section.
Alternatively :
The conductivity (s ) of a material is the reciprocal of its resistivity ( ρ ) ]
(Also accepts =
)
Its SI unit is
(
) ∕ ohm − 1 m − 1 ∕ ( . mho m − 1 ) ∕ siemen m − 1
(b) The acceleration,
= −
The average drift velocity,v d is given by
v d = −
τ
(τ = average time between collisions/ relaxation time)
Ifn is the number of free electrons per unit volume, the current I is given by
I = n e A | v d |
=
τ n | E |
ButI = | j | A ( j = current density )
We, therefore, get
| j | =
τ | E | ,
The term
τ is conductivity
∴ σ =
⇒ J = σ E
(b) Derivation of the expression for conductivity
Relation between current density and electric field
(a) The conductivity of a material equals to the reciprocal of the resistance of its wire of unit length and unit area of cross section.
Alternatively :
The conductivity (
(Also accept
Its SI unit is
(b) The acceleration,
The average drift velocity,
(
If
But
We, therefore, get
The term
© examsnet.com
Go to Question: