CBSE Class 12 Physics 2018 Delhi Set 1 Paper

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Question : 12
Total: 26
(a) Define the term 'conductivity' of a metallic wire. Write its SI unit.
(b) Using the concept of free electrons in a conductor, derive the expression for the conductivity of a wire in terms of number density and relaxation time. Hence obtain the relation between current density and the applied electric field E.
Solution:  
(a) Definition and SI unit of conductivity
(b) Derivation of the expression for conductivity
Relation between current density and electric field
(a) The conductivity of a material equals to the reciprocal of the resistance of its wire of unit length and unit area of cross section.
Alternatively :
The conductivity ( s ) of a material is the reciprocal of its resistivity (ρ) ]
(Also accept s=
1
ρ
)
Its SI unit is
(
1
ohm - metre
)
ohm 1m1(. mho m1) siemen m1
(b) The acceleration,
a
=
e
m
E

The average drift velocity, vd is given by
vd=
eE
m
τ

( τ= average time between collisions/ relaxation time)
If n is the number of free electrons per unit volume, the current I is given by
I=neA|vd|
=
e2A
m
τ
n
|E|

But I=|j|A(j= currentdensity)
We, therefore, get
|j|=
ne2
m
τ
|E|
,

The term
ne2
m
τ
is conductivity
σ=
ne2τ
m

J=σE
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