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Question : 25
Total: 26
(a) State the principle of an ac generator and explain its working with the help of a labelled diagram. Obtain the expression for the emf induced in a coil having N turns each of cross-sectional area A , rotating with a constant angular speed 'ω ' in a magnetic field B , directed perpendicular to the axis of rotation.
(b) An aeroplane is flying horizontally from west to east with a velocity of900 km ∕ hour . Calculate the potential difference developed between the ends of its wings having a span of 20 m . The horizontal component of the Earth's magneticfield is 5 × 10 − 4 T and the angle of dip is 30 ∘ .
OR
A deviceX is connected across an ac source of voltage V = V 0 s i n ω t . The current through X is given as I = I 0 s i n ( ω t +
) .
(a) Identify the deviceX and write the expression for its reactance.
(b) Draw graphs showing variation of voltage and current with time over one cycle of ac, forX .
(c) How does the reactance of the deviceX vary with frequency of the ac? Show this variation graphically.
(d) Draw the phasor diagram for the device X.
(b) An aeroplane is flying horizontally from west to east with a velocity of
OR
A device
(a) Identify the device
(b) Draw graphs showing variation of voltage and current with time over one cycle of ac, for
(c) How does the reactance of the device
(d) Draw the phasor diagram for the device X.
Solution:
(a) Principle of ac generator
working
Mark labelled diagram
Derivation of the expression for induced emf
(b) Calculation of potential difference
(a) The AC Generator works on the principle of electromagnetic induction.
When the magnetic flux through a coil changes, an emf is induced in it.
As the coil rotates in magnetic field the effective area of the loop, (i.e.A cos θ ) exposed to the magnetic field keeps on changing, hence magnetic flux changes and an emf is induced.
When a coil is rotated with a constant angular speed 'ω ', the angle ' θ ' between the magnetic field vector B and the area vector A , of the coil at any instant ' t ' equals ω t ; (assuming θ = 0 ∘ at t = 0 ) As a result, theeffective area of the coil exposed to the magnetic field changes with time; The flux at any instant ' t ' is given by
ϕ B = N B A cos θ = N B A cos ω t
∴ The induced emf e = − N
= − N B A
( cos ω t )
e = N B A ω s i n ω t
(b) Potential difference developed between the ends of the wings 'e ' = B l v
Given Velocityv = 900 km ∕ hour
= 250 m ∕ s
Wing span( l ) = 20 m
Vertical component of Earth's magnetic field
B v = B H tan δ
= 5 × 10 − 4 ( tan 30 ∘ ) Tesla
∴ Potential difference
= 5 × 10 − 4 ( tan 30 ∘ ) × 20 × 250
=
= 1.44 volt
OR
(a) Identification of the deviceX Expression for reactance
(b) Graphs of voltage and current with time
(c) Variation of reactance with frequency (Graphical variation)
(d) Phasor Diagram
(a)X : capacitor
ReactanceX c =
=
(b)
(c) Reactance of the capacitor varies in inverse proportion to the frequency i.e.,X c α
working
Mark labelled diagram
Derivation of the expression for induced emf
(b) Calculation of potential difference
(a) The AC Generator works on the principle of electromagnetic induction.
When the magnetic flux through a coil changes, an emf is induced in it.
As the coil rotates in magnetic field the effective area of the loop, (i.e.
When a coil is rotated with a constant angular speed '
(b) Potential difference developed between the ends of the wings '
Given Velocity
Wing span
Vertical component of Earth's magnetic field
OR
(a) Identification of the device
(b) Graphs of voltage and current with time
(c) Variation of reactance with frequency (Graphical variation)
(d) Phasor Diagram
(a)
Reactance
(b)
(c) Reactance of the capacitor varies in inverse proportion to the frequency i.e.,
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