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CBSE Class 12 Physics 2020 Outside Delhi Set 1 Paper

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Question : 30 of 37
Marks: +1, -0
(a) Differentiate between self inductance and mutual inductance.
(b) The mutual inductance of two coaxial coils is 2 H2\,\mathrm{H}. The current in one coil is changed uniformly from zero to 0.5 A0.5\,\mathrm{A} in 100 ms100\,\mathrm{ms}. Find the :
(i) change in magnetic flux through the other coil.
(ii) emf induced in the other coil during the change.
Solution:  
(a) In self inductance, the change in the strength of current in the coil is opposed by the coil itself by inducing an e.m.f.
In mutual inductance, a pair of coils are involved. If current changes in one coil, the other near by coil opposes the change by inducing an e.m.f. in itself.
(b) Induced emf =∣e∣=M  dIdt=2×  0.5100×10−3=5 V=\left|e\right| = M\; \frac{dI}{dt} = 2 \times \; \frac{0.5}{100 \times 10^{-3}} =5\,\mathrm{V}
    Induced emf  =∣e∣=  dϕdt\;\; \text{Induced emf}\;=\left|e\right|=\; \frac{d\phi}{dt}
          5=  dϕ100×10−3\; \;\;\;\; 5=\; \frac{d\phi}{100 \times 10^{-3}}
  dϕ=  change in flux  \; d\phi=\; \text{change in flux}\; =5×100×10−3=0.5 Wb=5 \times 100 \times 10^{-3} = 0.5\,\mathrm{Wb}
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