CBSE Class 12 Physics 2022 Term 2 Delhi Set 1 Solved Paper

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Question : 12
Total: 12
12. A ray of light travels from a denser to a rarer medium. After refraction, it bends away from the normal. When we keep increasing the angle of incidence, the angle of refraction also increases till the refracted ray grazes along the interface of two media. The angle of incidence for which it happens is called critical angle. If the angle of incidence is increased further the ray will not emerge and it will be reflected back in the denser medium. This phenomenon is called total internal reflection of light. 5
(i) A ray of light travels from a medium into water at an angle of incidence of 18°. The refractive index of the medium is more than that of water and the critical angle for the interface between the two media is 20°. Which one of the following figures best represents the correct path of the ray of light?

(ii) A point source of light is placed at the bottom of a tank filled with water, of refractive index mu, to a depth d. The area of the surface of water through which light from the source can emerge, is:
(A)
πd2
2(μ21)

(B)
πd2
(μ21)

(C)
πd2
2μ21

(D)
2πd2
(μ21)

(iii) For which of the following media, with respect to air, the value of critical angle is maximum?
(A) Crown glass
(B) Flint glass
(C) Water
(D) Diamond
(iv) The critical angle for a pair of two media A and B of refractive indices 2.0 and 1.0 respectively is:
(A) 0°
(B) 30°
(C) 45°
(D) 60°
(v) The critical angle of pair of a medium and air is 30circ. The speed of light in the medium is:
(A) 1×108ms1
(B) 1.5×108ms1
(C) 2.2×108ms1
(D) 2.8×108ms1
Solution:  
(i) Option (A) is correct.
Explanation: The angle of incidence is less than the critical angle. So, there will be normal refraction from denser to rarer medium and the refracted ray will move away from the normal.
(ii) Option (B) is correct.
Explanation:

r=dtanθc
sinθc=
1
μ

cosθc=1
1
μ2

r=d
1
μ
μ2
1
μ
=
d
μ21

area =πr2=
πd2
μ21


(iii) Option (C) is correct
Explanation:
Critical angle of glass is around 42°.
Critical angle of water is around 49°.
Critical angle of diamond is around 24°.
(iv) Option (B) is correct.
Explanation:
sinθC=
1
2

θC=30°
(v) Option (B) is correct.
Explanation:
θC=30°
μ=
1
sinθC
=
1
sin30°
=2

μ=
velocityoflightinvacuum
velocityoflightinthemedium

Or, 2=
3×108
velocityoflightinthemedium

Velocity of light in the medium
=1.5×108ms1
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