CBSE Class 12 Physics 2023 Delhi Set 1 Paper

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Question : 20
Total: 35
(a) How will the De Broglie wavelength associated with an electron be affected when the (i) velocity of the electron decreases ? and (ii) accelerating potential is increased? Justify your answer.
OR
(b) How would the stopping potential for a given photosensitive surface change if (i) the frequency of the incident radiation were increased? and (ii) the intensity of incident radiation were decreased? Justify your answer.
(a) (i) From De Broglie equation λ=
h
mv

As velocity (v) decreases, the wavelength (λ) increases.
(ii) λ=
h
2meV

As accelerating potential (V) increases, wavelength ( λ ) decreases.
OR
(b) (i) From Einstein's photoelectric equation,
hv=ϕ0+KE
KE=eVs, where VS is the stopping potential.
(i) Stopping potential depends on the frequency of the incident radiation. If frequency increases KE increases (Since, ϕ0 remains constant). Hence, stopping potential increases.
(ii) There is no intensity term in Einstein's equation. Hence, stopping potential is independent of intensity of incident radiation.
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