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Question : 20
Total: 35
(a) How will the De Broglie wavelength associated with an electron be affected when the (i) velocity of the electron decreases ? and (ii) accelerating potential is increased? Justify your answer.
OR
(b) How would the stopping potential for a given photosensitive surface change if (i) the frequency of the incident radiation were increased? and (ii) the intensity of incident radiation were decreased? Justify your answer.
OR
(b) How would the stopping potential for a given photosensitive surface change if (i) the frequency of the incident radiation were increased? and (ii) the intensity of incident radiation were decreased? Justify your answer.
Solution: 👈: Video Solution
(a) (i) From De Broglie equation λ =
As velocity( v ) decreases, the wavelength ( λ ) increases.
(ii)λ =
As accelerating potential (V) increases, wavelength (λ ) decreases.
OR
(b) (i) From Einstein's photoelectric equation,
h v = ϕ 0 + KE
KE = e V s , where V S is the stopping potential.
(i) Stopping potential depends on the frequency of the incident radiation. If frequency increasesKE increases (Since, ϕ 0 remains constant). Hence, stopping potential increases.
(ii) There is no intensity term in Einstein's equation. Hence, stopping potential is independent of intensity of incident radiation.
As velocity
(ii)
As accelerating potential (V) increases, wavelength (
OR
(b) (i) From Einstein's photoelectric equation,
(i) Stopping potential depends on the frequency of the incident radiation. If frequency increases
(ii) There is no intensity term in Einstein's equation. Hence, stopping potential is independent of intensity of incident radiation.
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