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Question : 33
Total: 35
(a) (i) Draw a ray diagram to show the working of a compound microscope. Obtain the expression for the total magnification for the final image to be formed at the near point.
(ii) In a compound microscope an object is placed at a distance of1.5 cm from the objective of focal length 1.25 cm . If the eye-piece has a focal length of 5 cm and the final image is formed at the near point, find the magnifying power of the microscope.
OR
(b) (i) Draw a ray diagram for the formation of image of an object by an astronomical telescope, in normal adjustment. Obtain the expression for its magnifying power.
(ii) The magnifying power of an astronomical telescope in normal adjustment is2 . 9 and the objective and the eyepiece are separated by a distance of 150 cm . Find the focal lengths of the two lenses.
(ii) In a compound microscope an object is placed at a distance of
OR
(b) (i) Draw a ray diagram for the formation of image of an object by an astronomical telescope, in normal adjustment. Obtain the expression for its magnifying power.
(ii) The magnifying power of an astronomical telescope in normal adjustment is
Solution: 👈: Video Solution
(a) (i) Ray diagram of compound microscope:
In a compound microscope there are two lenses - objective( O ) and Eyepiece ( E ) .
ObjectP Q is placed in front of the objective at a distance more than the focal length of the objective.
An inverted, magnified, real imageP 1 Q 1 is formed in front of eyepiece within the optical centre and the focus of the eyepiece. This acts as the object of the eyepiece. An (erect with respect to P 1 Q 1 , inverted with respect to P Q ), magnified, virtual image P 2 Q 2 is formed at a distance D (minimum distance of distinct vision) from the eyepiece.
Magnification:
For objective:
Object distance= u
Image distance= v
Magnification = m o =
=
Applying the lens formula,
−
=
Or,1 +
=
Or,
=
− 1
For eyepiece:
Magnification = m e = 1 +
Magnification of the combination of objective and eyepiece= m = m O × m e
Or, m =
× ( 1 +
)
Or, m = (
− 1 ) ( 1 +
)
P 1 Q 1 image is formed very close to the eyepiece, hence v can be approximated as the distance between the two lenses i.e., the length of the tube(L).
∴ m = (
− 1 ) ( 1 +
)
Since,f e ≪ D and f 0 ≪ L , hence the above expression may be approximated as,
m =
×
(ii) Given,u = 1.5 cm , f 0 = 1.25 cm , f e = 5 cm , D = 25 cm
Here, all alphabets are in their usual meanings Applying lens formula for objective lens,
−
=
Or,
−
=
∴ v = 7.5 cm
Magnification= m =
× ( 1 +
)
Or, m =
× ( 1 +
)
∴ m = − 30
OR
(b) (i) Astronomical telescope in normal adjustment:
In an astronomical telescope there are two lenses - objective( O ) and Eyepiece ( E ) .
The two lenses are so placed during focussing that the foci of the lenses meet at a point.
Objective is directed towards the object at infinity.
Parallel rays coming from the object meet at the focus of the objective and forms an inverted, real imageP 1 Q 1 in front of eyepiece. This point is the focus of eyepiece too.
This acts as the object of the eyepiece. An (inverted with respect toP 1 Q 1 , erect with respect to original object), highly magnified, real image is formed at infinity.
Magnification= m
=
Or,m =
Or,m =
Or, m =
Or, m =
[α and β being very small, tan α = α and tan β = β ]
Or,m =
Or,m =
∴m =
(ii) Since, m =
Or, 2.9 =
∴ f o = 2.9 f e
Also, f o + f e = 150
Or, 2.9 f e + f e = 150
∴ f e =
= 38.46 cm
f O = 2.9 f c
= 2.9 × 38.46
= 111.54 cm
In a compound microscope there are two lenses - objective
Object
An inverted, magnified, real image
Magnification:
For objective:
Object distance
Image distance
Applying the lens formula,
Or,
Or,
For eyepiece:
Magnification of the combination of objective and eyepiece
Since,
(ii) Given,
Here, all alphabets are in their usual meanings Applying lens formula for objective lens,
Magnification
OR
(b) (i) Astronomical telescope in normal adjustment:
In an astronomical telescope there are two lenses - objective
The two lenses are so placed during focussing that the foci of the lenses meet at a point.
Objective is directed towards the object at infinity.
Parallel rays coming from the object meet at the focus of the objective and forms an inverted, real image
This acts as the object of the eyepiece. An (inverted with respect to
Magnification
Or,
Or,
[
Or,
Or,
∴
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