In an extrinsic semiconductor, the number ...

CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

Question : 13 of 35

Marks: +1, -0

In an extrinsic semiconductor, the number density of holes is

4 \times 10^{20} \mathrm{m}^{-3}

. If the number density of intrinsic carriers is

1.2 \times 10^{15} \mathrm{m}^{3}

, the number density of electrons in it is

Solution: 👈: Video Solution

From law of mass action,

n_i^2 = n_e \times n_h

or,

(1.2 \times 10^{15})^2 = n_e \times 4 \times 10^{20}

or,

\; n_e = (0.3 \times 1.2) \times 10^{10}

∴

\; n_e = 3.6 \times 10^9 \mathrm{m}^{-3}

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