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CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 2 of 35
Marks: +1, -0
A point PP lies at a distance xx from the mid point of an electric dipole on its axis. The electric potential at point PP is proportional to
Expression for electric potential due to dipole in given as V=14πε0px2V = \frac{1}{4 \pi \varepsilon_0} \frac{p}{x^2}
So, V1x2V \propto \frac{1}{x^2}
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