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CBSE Class 12 Physics 2025 All Sets Solved Paper

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Question : 6 of 16
Marks: +1, -0
A voltage v=v0v = v_0 sinωt\sin\omega t applied to a circuit drives a current i=i0i = i_0 sin(ωt+φ)\sin(\omega t + \varphi) in the circuit. The average power consumed in the circuit over a cycle is
Solution:  
The instantaneous power in an AC circuit is given by:
P=Vi=V0sin(ωt)×i0sin(ωt+φ)P = Vi = V_0 \sin(\omega t) \times i_0 \sin(\omega t + \varphi)
Using the average power formula over a cycle:
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