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ICSE Class 10 Chemistry 2020 Paper

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Question : 27 of 86
Marks: +1, -0
The volume occupied by 80 g80\ \mathrm{g} of carbon dioxide at STP.
Solution:  
Molecular mass of CO2\mathrm{CO}_2
=12+16×2=44 gm=12+16 \times 2=44\ \mathrm{gm}
If vol. occupied by 44 gm CO244\ \mathrm{gm}\ \mathrm{CO}_2 at STP =22.4 l=22.4\ \mathrm{l}
Then vol. occupied by 80 gm CO280\ \mathrm{gm}\ \mathrm{CO}_2 at STP
  =  22.444×80\;=\;\frac{22.4}{44} \times 80
  =40.72 l    or   40720 ml\;=40.72\ \mathrm{l}\ \;\text{ or }\; 40720\ \mathrm{ml}
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