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ICSE Class 10 Chemistry 2020 Paper

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Question : 28 of 86
Marks: +1, -0
Calculate the number of molecules in 4.4 gm\text{gm} of CO2\mathrm{CO}_2 .
[Atomic mass of C=12,O=16\mathrm{C}=12, \mathrm{O}=16 ]
Solution:  
Molecular mass of CO2\mathrm{CO}_2
=12+16×2  =44gm=12+16 \times 2\;=44 \text{gm}
  No. of Moles    =  wt.ingm    GMM  \;\text{No. of Moles}\;\;=\frac{\;\text{wt.ingm}\;}{\;\text{GMM}\;}
  =4⋅444=0.1moles\;=\frac{4 \cdot 4}{44}=0.1 \text{moles}
No. of molecules
  =Mole  ×  Avogadros number  \;=\text{Mole}\; \times \;\text{Avogadros number}\;
  =0.1×6.023×1023\;=0.1 \times 6.023 \times 10^{23}
  =0.6023×1023  Molecules  \;=0.6023 \times 10^{23} \;\text{Molecules}\;
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