ICSE Class 10 Physics 2014 Solved Paper

Question : 31

Total: 66

Two forces each of 5N act vertically upwards and downwards respectively on the two ends of a uniform metre rule which is placed at its mid-point as shown in the diagram. Determine the magnitude of the resultant moment of these forces about the midpoint.

Solution:

Given : F1=F2=5N,d1=d2=0.5m
Torque τ=F×d
τ1‌=F1×d1=5N×0.5m
‌=2.5‌Nm‌‌‌ (Anti-clockwise) ‌
τ2‌=F2×d2=5N×0.5m
‌=2.5‌Nm‌‌‌ (Anti-clockwise) ‌
The resultant moment of force
‌=τ1+τ2=2.5+2.5
‌=5‌Nm‌ in Anti clockwise direction. ‌

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