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ICSE Class 10 Physics 2016 Solved Paper

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Question : 21
Total: 73
Calculate the quantity of heat produced in a 20Ω resistor carrying 2.5A current in 5 minutes.
Solution:  
Given :I=2.5‌Amp,R=20Ω,t=5×60= 300 second.
‌ Head Produced ‌=
(‌ Potential Difference ‌)
Volts
 ×
(‌ Current ‌)
Ampere
×
(‌ time ‌)
Second
=VIt
=‌I2Rt‌‌(‌ Ohm's law, V=IR ‌)
=‌‌
25
10
×‌
25
10
×20×300
=‌37500J
=‌37.5‌kJ.
Hence, 37.5‌kJ heat is produced.
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