A boy uses a single fixed pulley to lift a ...

ICSE Class 10 Physics 2017 Paper

Question : 25 of 65

Marks: +1, -0

A boy uses a single fixed pulley to lift a load of

50\,\text{kgf}

to some height. Another boy uses a single movable pulley to lift the same load to the same height. Compare the effort applied by them. Give a reason to support your answer.

Solution:

Given

:

Load

=50\,\text{kgf}

For a single fixed pulley in ideal case, M.A.

=1

\because\ \text{M.A.}=\frac{\text{Load}}{\text{Effort}}

\text{or}\ \text{Effort}=\frac{\text{Load}}{\text{M.A.}}

=\frac{50\,\text{kgf}}{1}=50\,\text{kgf}

For a single movable pulley in ideal case, M.A.

=2

\therefore\ \text{Effort}=\frac{\text{Load}}{\text{M.A.}}

=\frac{50\,\text{kgf}}{2}=25\,\text{kgf}\ \text{.}

\therefore

Ratio of effort by a single fixed pulley : Effort applied by a single movable pulley

=50\,\text{kgf}: 25\,\text{kfg}\ .

=2: 1

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