Test Index

ICSE Class X Math 2016 Paper

Show Para  Hide Para 
The slope of a line joining P(6,k)P(6,k) and Q(1−Q(1- 3k,3)3k,3) is   12\;\frac{1}{2}. Find:
© examsnet.com
Question : 4 of 57
Marks: +1, -0
kk
Solution:  
Let P(6,k)=(x1,y1)P(6, k) = (x_1, y_1) and Q(1−3k,3)=Q(1-3k, 3) = (x2,y2)(x_2, y_2)
∴       Slope of   PQ  =  y2−y1x2−x1\therefore \;\; \;\text{ Slope of }\; PQ\;=\;\frac{y_2-y_1}{x_2-x_1}
⇒      3−k1−3k−6  =  12\Rightarrow \;\; \;\frac{3-k}{1-3k-6}\;=\;\frac{1}{2}
6−2k  =−5−3k6-2k\;=-5-3k
11  =−k11\;=-k
k  =−11k\;=-11
© examsnet.com
Go to Question:
Prev Question
Next Question