NCERT Class XI Chemistry Classification of Elements and Periodicity in Properties Solutions

Question : 15

Total: 40

Energy of an electron in the ground state of the hydrogen atom is –2.18 × 10–18 J. Calculate the ionization enthalpy of atomic hydrogen in terms of Jmol–1. [Hint : Apply the idea of mole concept to derive the answer]

Solution:

Energy of the electron in the ground state of H-atom, E1 = –2.18 × 10–18 J
Ionisation energy = E∞–En
Ionisation enthalpy per mole of atomic hydrogen = (E∞–E1) NA
= [0 – (– 2.18 × 10–18)] × 6.023 × 1023
= 2.18 × 6.023 × 105 J/mol = 13.13 × 105 J/mol
= 1.313 × 106 J/mol

Go to Question:

Prev Question

Next Question