NCERT Class XI Chemistry Equilibrium Solutions
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Question : 18
Total: 73
Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as :
C H 3 C O O H ( l ) + C 2 H 5 O H ( l ) C H 3 C O O C 2 H 5 ( l ) + H 2 O ( l )
(i) Write the concentration ratio (reaction quotient),Q c
(ii) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture.
Calculate the equilibrium constant.
(iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime.
Has equilibrium been reached?
(i) Write the concentration ratio (reaction quotient),
(ii) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture.
Calculate the equilibrium constant.
(iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime.
Has equilibrium been reached?
Solution:
(i) Q c
(ii)C H 3 C O O H + C 5 H 5 O H C H 2 C O O C 2 H 5 + H 2 O
Initially
n C H 3 C O O H n C 2 H 5 O H n C H 3 C O O C 2 H 5 n h 2 O
At equilibrium :
n C H 3 C O O H n C 2 H 5 O H
n C H 3 C O O C 2 H 5 n H 2 O
K =
(iii)C H 3 C O O H + C 2 H 5 O H C H 3 C O O C 2 H 5 + H 2 O
Initial
n C H 3 C O O H n C 2 H 5 O H n C H 3 C O O C 2 H 5 n H 2 O
At equilibrium,
n C H 3 C O O H
n C 2 H 5 O H
n C H 3 C O O C 2 H 5 n H 2 O
Q c
AsQ c
(ii)
Initially
At equilibrium :
K =
(iii)
Initial
At equilibrium,
As
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