NCERT Class XI Chemistry Equilibrium Solutions
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Question : 30
Total: 73
At 473 K, equilibrium constant K c for decomposition of phosphorus pentachloride, P C l 5 is 8.3 × 10 – 3 . If decomposition is depicted as :
P C l 5 ( g ) ⇌ P C l 3 ( g ) + C l 2 ( g ) ; Δ r H ° = 124.0 k J mol – 1
(a) Write an expression for Kc for the reaction.
(b) What is the value of Kc for the reverse reaction at the same temperature?
(c) What would be the effect onK c if
(i) moreP C l 5 is added
(ii) pressure is increased
(iii) the temperature is increased?
(a) Write an expression for Kc for the reaction.
(b) What is the value of Kc for the reverse reaction at the same temperature?
(c) What would be the effect on
(i) more
(ii) pressure is increased
(iii) the temperature is increased?
Solution:
(a) K c =
(b)P C l 3 ( g ) + C l 2 ( g ) ⇌ P C l 5 ( g )
∴K c ′ =
(c)P C l 5 ( g ) ⇌ P C l 3 ( g ) + C l 2 ( g )
(i) If moreP C l 5 is added, then Q c becomes less than Kc, the reaction will shift in the forward direction.
(ii) If the pressure is increased, the reaction will shift towards backward direction as it contains less number of gaseous species.
(iii) As the reaction is endothermic, the increase in temperature will favour the forward reaction. MoreP C l 5 will dissociate to form P C l 3 and C l 2 .
(b)
∴
(c)
(i) If more
(ii) If the pressure is increased, the reaction will shift towards backward direction as it contains less number of gaseous species.
(iii) As the reaction is endothermic, the increase in temperature will favour the forward reaction. More
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