NCERT Class XI Chemistry Equilibrium Solutions
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Question : 55
Total: 73
Calculate the hydrogen ion concentration in the following biological fluids whose pH are given below:
(a) Human muscle-fluid, 6.83
(b) Human stomach fluid, 1.2
(c) Human blood, 7.38
(d) Human saliva, 6.4.
(a) Human muscle-fluid, 6.83
(b) Human stomach fluid, 1.2
(c) Human blood, 7.38
(d) Human saliva, 6.4.
Solution:
(a) pH = 6.83
∴[ H + ] = antilog(– 6.83) = 1.48 × 10 – 7 M
(b) pH = 1.2
∴[ H + ] = antilog(–1.2) = 6.30 × 10 – 2 M
(c) pH = 7.38
∴[ H + ] = antilog (– 7.38) = 4.17 × 10 − 8 M
(d) pH = 6.4,
∴[ H + ] = antilog(–6.4) = 3.98 × 10 – 7 M
∴
(b) pH = 1.2
∴
(c) pH = 7.38
∴
(d) pH = 6.4,
∴
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