In the estimation of sulphur by Carius ...

NCERT Class XI Chemistry Organic Chemistry Some basic principles and Techniques Solutions

Question : 35 of 40

Marks: +1, -0

In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

Solution:

Given : Mass of organic sulphur compound = 0.468 g

Mass of

\mathrm{BaSO}_4

= 0.668 g; 1 mol of

\mathrm{BaSO}_4

= 233 g

233 g of

\mathrm{BaSO}_4

contains 32 g of S

∴ 0.668 g of

\mathrm{BaSO}_4

contains

\frac{0.668 \times 32}{233}

= 0.09174 g

0.09174 g S is present in 0.468 g of the compound.

% of S in compound =

\frac{0.09174}{0.468}

× 100 = 19.6 %

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