NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

Question : 8

Total: 36

Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively.

Solution:

For empirical formula, Refer Ans. 3
Molecular mass of Fe2O3 = 2 × 56 + 3 × 16 = 112 + 48 = 160
Molecular formula = n (Empirical formula)
∴ n =

Molecular‌mass

Emperical‌formula‌mass

160

⇒ n = 1
∴ Molecular formula = (Fe2O3) × 1 = Fe2O3

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