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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 11
Total: 67
A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57 µm. Calculate the rate of emission of quanta per second.
Solution:  
Power of bulb = 25 watt =
work
time
 = 25 Js−1
Energy of photon (E) =
hc
λ
 =
6.626×10−34×3×108
0.57×10−6
 [Since 1 µm = 10−6 m]
Rate of emission of quanta per second =
25
24.87×10−20
 = 0.7169 × 1020
= 7.169 × 1019s−1
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