NCERT Class XI Chemistry Structure of Atom Solutions
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Question : 44
Total: 67
An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol of this ion.
Solution:
Let the number of protons(p) = x
∴ Number of electrons (e) = x – 3 (because the ion carries 3 units of positive charge, it will have 3 electrons less than the number of protons.)
Number of neutrons(n)
= (x - 3) +
n =
We know that A = p + n
56 = x +
or 5600 = 230.4x – 391.2 or 5600 + 391.2 = 230.4x or 5991.2 = 230.4x
∴ x =
Thus, number of protons (p) = 26, number of electrons (e) = 26 – 3 = 23
therefore, symbol of the ion =
F e 3 +
∴ Number of electrons (e) = x – 3 (because the ion carries 3 units of positive charge, it will have 3 electrons less than the number of protons.)
Number of neutrons(n)
= (x - 3) +
n =
We know that A = p + n
56 = x +
or 5600 = 230.4x – 391.2 or 5600 + 391.2 = 230.4x or 5991.2 = 230.4x
∴ x =
Thus, number of protons (p) = 26, number of electrons (e) = 26 – 3 = 23
therefore, symbol of the ion =
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