NCERT Class XI Chemistry Structure of Atom Solutions

Question : 50

Total: 67

The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.

Solution:

Step I : Wavelength (λ) = 589 nm = 589 × 10–9m
Frequency (u) =

3×108

589×10−9

= 50.93 × 1014 cycles per sec
Step II : Wavelength (λ) = 589.6 nm = 589.6 × 10–9m
∴ v =

3×108

589.6×10−9

= 5.088 × 1014 cycles per sec
Energy difference between two excited states,
ΔE = 6.626 × 10–34 (5.093 – 5.088) 1014 = 6.626 × 10–34 × 5 × 10–3 × 1014
= 3.31 × 10–22J

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