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NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 17 of 36
Marks: +1, -0
(x2−y)6(x^2-y)^6
Solution:  
We have given (x2−y)6(x^2-y)^6 = (x2+(−y))6(x^2+(-y))^6
∴ The general term is Tr+1T_{r+1} =   ⁣6Cr(x2)6−r(−y)r\,\!{}^{6}C_{r} (x^2)^{6-r} (-y)^r
=   ⁣6Crx12−2r(−1)ry2\,\!{}^{6}C_{r} x^{12-2r} (-1)^r y^2 = (−1)66Crx12−2ryr(-1)^6 {}^{6}C_{r} x^{12-2r} y^r
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