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NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 18 of 36
Marks: +1, -0
(x2−yx)12(x^2 - yx)^{12} , x ≠ 0
Solution:  
We have given (x2−yx)12(x^2 - yx)^{12} = (x2+(−y))12(x^2 + (-y))^{12} , x ≠ 0
∴ The general term is Tr+1T_{r+1} = 12Cr(x2)12−r(−yx)r{}^{12}C_r (x^2)^{12-r} (-yx)^r
=  12Crx24−2r(−1)ryrxr\,{}^{12}C_r x^{24-2r} (-1)^r y^r x^r = (−1)r 6Crx24−2r+ryr(-1)^r \,{}^{6}C_r x^{24-2r+r} y^r = (−1)r 12Crx24−ryr(-1)^r \,{}^{12}C_r x^{24-r} y^r
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