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NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 4 of 72
Marks: +1, -0
lim⁡x→44x+3x−2\lim\limits_{x\to 4}\frac{4x+3}{x-2}
Solution:  
We have lim⁡x→44x+3x−2\lim\limits_{x\to 4}\frac{4x+3}{x-2} = 4(4)+3x−2\frac{4(4)+3}{x-2} = 192\frac{19}{2}
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