NCERT Class XI Mathematics - Probability - Solutions

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Question : 26
Total: 54
A die is thrown, find the probability of following events:
(i) A prime number will appear;
(ii) A number greater than or equal to 3 will appear;
(iii) A number less than or equal to one will appear;
(iv) A number more than 6 will appear;
(v) A number less than 6 will appear.
Solution:  
An experiment consists of throwing a die.
∴ The sample space of the experiment is given by S = {1, 2, 3, 4, 5, 6}
(i) Let E be the event that a prime number will appear. E = {2, 3, 5}
∴ P (E) =
n(E)
n(S)
=
3
6
=
1
2

(ii) Let F be the event that a number ≥ 3 will appear. F = {3, 4, 5, 6}
∴ P (F) =
n(F)
n(S)
=
4
6
=
2
3

(iii) Let G be the event that a number ≤ 1 will appear. G = {1}
∴ P (G) =
n(G)
n(S)
=
1
6

(iv) Let H be the event that a number more than 6 will appear. H = ϕ
∴ P (H) =
n(H)
n(S)
=
0
6
= 0
(v) Let I be the event that a number less than 6 will appear. I = {1, 2, 3, 4, 5}
∴ P (I) =
n(I)
n(S)
=
5
6
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