NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 59
Total: 106
If a, b, c and d are in G.P., show that
(a2+b2+c2)(b2+c2+d2) = (ab+bc+cd)2
Solution:  
We have a, b, c, d are in G.P.
Let r be a common ratio, then b = ar, c = ar2, d = ar3
(a2+b2+c2)(b2+c2+d2)
= [a2+(ar)2+(ar2)2] [(ar)2+(ar2)2+(ar3)2] = [a2+a2r2+a2r4] [a2r2+a2r4+a2r6]
= a2(1+r2+r4)a2r2(1+r2+r4)
= a4r2(1+r2+r4)2 ....(i)
Also, (ab+bc+cd)2 = (a2r+a2r3+a2r5)2
= a4r2(1+r2+r4)2 ....(ii)
From (i) & (ii), we get (a2+b2+c2)(b2+c2+d2) = (ab+bc+cd)2.
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