Suppose the given points are A and B.
Let M be the mid point of AB.

∴ M = (

3+(−1)

2

,

4+2

2

) = (1 , 3)
Slope of AB =

2−4

−1−3

=

−2

−4

=

1

2

∴ Slope of the right bisector is –2.
Since the right bisector passes through M(1, 3),
∴ The equation of the right bisector is y – 3 = –2 (x – 1) ⇒ 2x + y – 5 = 0
Hence the required equation is 2x + y = 5.