Given equation is √3x + y + 2 = 0.
or, √3x + y = - 2 or, - √3 x + (- 1) y = 2
⇒ (−

√3

2

)x+(−

1

2

)y = 1
⇒ (– cos 30°)x + (– sin 30°)y = 1
⇒ x cos (180° + 30°) + y sin (180° + 30°) = 1
⇒ x cos 210° + y sin 210° = 1
Comparing the above equation with x cos θ + y sinθ = p, we get θ = 210°
and p = 1 i.e., θ = 210° =

210π

180

=

7π

6

.