Mechanical Properties of Fluids

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Question : 10
Total: 31
In the previous problem, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)
Solution:  
On pouring 15 cm of water and spirit each into the respective arms of the U-tube, the mercury level will rise in the arm containing the spirit.
ρm= density of mercury.
Let us select two points A and B lying in the same horizontal plane asshown.
Thus according to Pascal’s law,
Pressure at A= Pressure at B
or P0+hwρwg=P0+hsρsg+hmρmg
where P0= atmospheric pressure
or hwρw=hsρs+hmρm
or hmρm=hwρwhsρs
Here, hw= height of water column =10+15=25 cm
hs= height of spirit column =12.5+15=27.5 cm
ρw=1g cm3;ρs=0.8 g cm3
ρm= density of mercury =13.6 g cm3
∴ Substituting in equation (i), we get
hm×13.6=25×127.5×0.8
or hm=
2522.00
13.6

=0.2206 cm
=0.221 cm or hm=0.221 cm
i.e. mercury will rise in the arm containing spirit, by 0.221 cm
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