Mechanical Properties of Fluids
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Question : 8
Total: 31
A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2
Solution:
The maximum force, which the bigger piston can bear,
F = 3000 k g , f = 3000 × 9.8 N
∴ Maximum pressure on the bigger piston,
P =
=
= 6.92 × 10 5 P a
Since the liquid transmits pressure equally, therefore the maximumpressure the smaller piston can bear is6.92 × 10 5
∴ Maximum pressure on the bigger piston,
Since the liquid transmits pressure equally, therefore the maximumpressure the smaller piston can bear is
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