Test Index

Motion in a Plane

© examsnet.com
Question : 13 of 32
Marks: +1, -0
A man can swim with a speed of 4.0 km h−1^{-1} in still water. How long does he take to cross a river 1.0 km wide if the river flows steadily at 3.0 km h−1^{-1} and he makes his strokes normal to the river current? How far down the river does he go when he reaches the other bank?
Solution:  
Speed of man, vx=4v_x = 4 km h−1^{-1}
Distance travelled = 1 km
Speed of river = 3 km h−1^{-1}If t = time taken to cross the river
Then, t=DistanceSpeedt = \frac{\text{Distance}}{\text{Speed}} =1 km4 kmh−1=14= \frac{1\,\text{km}}{\frac{4\,\text{km}}{\text{h}^{-1}}} = \frac{1}{4} hour =15=15 minutes
The man is carried down by stream with velocity of river water.
∴ Distance travelled by man in 15 min (or 14 h)\text{min}\ \left( \text{or } \frac{1}{4}\,\text{h} \right) is
=3 km h−1×14 h=750 m= 3\,\text{km}\,\text{h}^{-1} \times \frac{1}{4}\,\text{h} = 750\,\text{m}
© examsnet.com
Go to Question: